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JEE Main Exam Pattern 2023 - Marking Scheme, Paper Pattern, Mode & Duration

Updated By Mahima Bahl on 21 Mar, 2023 22:04

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JEE Main 2023 Exam Pattern

The National Testing Agency (NTA) has released the exam pattern of JEE Main 2023 at jeemain.nta.nic.in. The JEE Main exam pattern is released along with the official brochure of JEE Main exam 2023. The exam pattern of JEE Main throws light on the format of the exam, the number of sections, the types of questions, and other important information. 

Each topic will have two parts in the JEE Main 2023 examination paper. Section A will have 20 required multiple-choice questions, but Section B will include 10 numerical questions, of which students must answer just five. Both Section A and Section B will receive negative marking. The students should insert the right integer value of the answer for each question in Section B using the mouse and the on-screen virtual numeric keypad in the location indicated to enter the answer. Section B requires the answer to be rounded to the nearest Integer.

JEE Main exam 2023 is being conducted in two sessions having two papers - Paper 1 (B.E/B.Tech) and Paper 2 (B.Arch or B.Plan). As per the paper pattern, the optional questions will have negative marking this year similar to last year. The candidates must note that Section B consists of numerical questions, and he/ she will have the option to answer any five questions out of 10. There will be no choice in Section A. Candidates preparing for the JEE Main exam can download the admit card of JEE Main 2023 in online mode.

Also Read - JEE Main 2023 Preparation and Study Time Table

JEE Main 2023 Latest Updates

Highlights of JEE Main Exam Pattern 2023

Particulars

Details

Mode of Exam

Online (Computer-based test)

Papers in Exam

3 in total

Duration 

3 hours (180 minutes)

Marking Scheme

Four points will be awarded for each correct response, and one point will be deducted for each incorrect answer.

Question Type

MCQs, numerical type questions, and aptitude drawing questions (only paper 2A and 2B)

What's new in the JEE Main 2023 exam pattern?

Once NTA has released the official exam pattern of JEE Main 2023, we can compare the exam pattern with the previous one and understand the new changes. To understand the comparison, let us look at the changes that were prevalent in the previous year JEE Main exam pattern.

  • The NTA JEE Main 2023 test will include two examinations, with Paper 1 being for B.Tech/B.E. Paper 2 is for the B.Arch. as well as B.Plan
  • Paper 1 for B.Tech candidates is divided into three portions, with 25 questions for each subject (Physics, Chemistry, and Mathematics)
  • The total score is 300
  • For the B.Arch. Paper 2 is held separately for B.Plan candidates and is divided into two papers, Paper 2A and Paper 2B
  • Except for the drawing component of Paper 2A, the JEE Main 2023 exam will be administered online
  • Paper 2A is for B.Arch applicants and will consist of 82 questions worth 400 points, while Paper 2B is for B.Plan candidates and will consist of 105 MCQs for 400 points

Changes in JEE Main Exam Pattern

JEE Main Exam Pattern 2023 of Paper 1 (B.E/B.Tech)

Students should be aware of the JEE Main 2023 test pattern in order to understand the examination method, type of questions, total number of sections, marking scheme, and so on. The JEE Main 2023 exam pattern is available in the table below.

Paper 1 (B.E/B.Tech) Exam Pattern

Factors

Details

Mode of Exam

CBT (Computer-based examination)

Exam Duration

3 hours/180 minutes

Language of Examination

English, Hindi, Marathi, Assamese, Tamil Bengali,Kannada,Punjabi, Gujarati, Odia, Telugu, Malayalam and Urdu.

Type of Questions

  • Multiple choice questions (MCQs)
  • Questions with numerical responses

No. of Sections

Three are three sections:

  • Physics
  • Chemistry
  • Mathematics

No. of Questions

Mathematics: 25 (20+10) 10 questions with numerical answers Five of the ten questions are required.

Physics: 25 (20+10) points for physics 10 questions, each with a number answer. Five of the ten questions are required.

Chemistry: 25 (20+10) 10 questions with numerical answers Five of the ten questions are required.

75 questions in total (25 questions each)

Total Marks

300 Marks (100 marks for each section)

JEE Main Marking Scheme

MCQs: Each correct answer will be worth four points, while each incorrect response will be worth one point.

Questions with numerical value answers: Candidates will receive four marks for each correct answer and one mark for each incorrect response.

Tie Breaking Policy for JEE Main Paper I

If two or more candidates score the same marks in JEE Main Paper I exam, the order of merit will be determined as per the following tie-breaking rules. In order to make the candidates have a detailed understanding of tie-breaking policy, we have explained the same with some examples.

Tie Breaker 1: Candidates scoring higher marks in Mathematics will be given priority in the merit list as per tie-breaker policy - 1.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. However, Candidate A scored 80 marks in Mathematics, while Candidate B scored 82 in Mathematics. Here, Candidate B will be given priority in the merit list as per the Tie Breaker Policy 1.

Tie Breaker 2: This policy comes into effect only if two or more candidates score the same marks in Mathematics. Since two or more candidates have similar marks in Mathematics, the marks scored by candidates in Physics will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 in JEE Main Paper I. Both of them have also scored 80 marks in Mathematics. However, Candidate A scored 85 in Physics and Candidate B scored 82 in Physics. As per the tie-breaker policy 2, Candidate A will be given higher preference in the merit list than Candidate B.

Tie Breaker 3: This policy comes into effect only if two or more candidates score similar marks in Physics. In such cases, marks scored by candidates in Chemistry will be taken into consideration to determine the merit.

Example:

Let us assume that Candidate A and Candidate B have scored 280 out of 300 marks in JEE Main Paper I. On the other hand, both these candidates scored the same marks in the Mathematics and Physics section of the exam. However, Candidate A scored 80 marks in Chemistry and Candidate B scored 81 marks. As per tie-breaker policy 3, Candidate B will be given a higher preference in the merit list than Candidate A.

Tie Breaker 4: This policy comes into effect only if two or more candidates score the same marks in Mathematics, Physics and Chemistry sections of JEE Maine Paper I. In such cases, the candidate with less number of negative responses in the exam will be given higher preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper I. On the other hand, both these candidates score the same marks in Mathematics, Physics and Chemistry. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if a tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper I. On the other hand, these candidates scored same marks in Mathematics, Physics and Chemistry. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

JEE Main 2023 Exam Pattern for Paper 2

JEE Main Paper II exam pattern 2023, marking scheme and tie-breaking policy can be checked below -

Exam Pattern for JEE Main 2023 Paper 2A (B.Arch)

Subjects

Number of Questions

Marks

Mathematics

25 (20+10*)

5 out of 10* questions with numerical answers must be answered.

100

Aptitude

50

200

Drawing Test

2

100

Total

82 Questions

400 Marks

JEE Main 2023 Exam Pattern: Paper 2B (B.Plan)

Subjects

Number of Questions

Marks

Mathematics

25 (20+10*)

5 out of 10* questions with answers as a numerical value have to be answered.

100

Aptitude

50

200

Planning Test

25

100

Total

105 Questions

400 Marks

Marking Scheme for JEE Main Paper II

Name of the Section

Marking Scheme

MCQ-Based Questions

Marks for Correct Answer

04

Negative Mark for Incorrect Answer

-1

Negative Mark for Unanswered/ Marked for Review Questions

0

Numerical Value Questions

Marks for Correct Answer

04

Negative Mark for Incorrect Answer

Yes

Negative Mark for Unanswered/ Marked for Review Questions

0

Drawing Test Part III

Two Questions will be evaluated for 100 marks.

-

Tie Breaking Policy for JEE Main Paper II

If two or more candidates secure the same marks in JEE Main Paper II exam, the below rules or tie-breaking policy will be applied to determine the merit of candidates.

Tie Breaker 1:Candidates scoring higher marks in Mathematics in JEE Main Paper II will be given preference in the merit list as per tie-breaker policy 1.

Example:

Let us assume that Candidate A and Candidate B have scored 360 out of 400 marks in JEE Main. However, Candidate A scored 79 marks in Mathematics and Candidate B scored 81 marks. The preference in the order of merit will be given to Candidate B, as he scored higher marks in Mathematics than Candidate A.

Tie Breaker 2: This policy comes into effect when two or more candidates score the same marks in Mathematics. In such cases, candidates with higher marks in the Aptitude Test will be given higher preference in the merit list.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 marks in JEE Main. However, Candidate A scored 140 marks in Paper-II, while Candidate B scored 139 marks. In such cases, Candidate A will be given higher preference in the order of merit than Candidate B.

Tie Breaker 3: This policy comes into effect if two or more candidates score the same marks in Mathematics and Aptitude Test. In such cases, candidates with higher marks in Drawing Test will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 350 out of 400 in JEE Main Paper-II. On the other hand, these candidates have also scored the same marks in Mathematics and Aptitude Test. However, Candidate A scored 78 marks on Drawing Test and Candidate B scored 80 marks. In such cases, Candidate B will be the higher preference in the merit list, as he scored higher marks in Drawing Test than Candidate A.

Tie Breaker 4: This policy comes into effect if two or more candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. In such cases, candidates with fewer negative answers or incorrect answers in JEE Main Paper-II exam will be given preference in the order of merit.

Example:

Let us assume that Candidate A and Candidate B have scored 250 marks in JEE Main Paper-II. On the other hand, both these candidates score the same marks in Mathematics, Aptitude Test and Drawing Test. However, the number of wrong answers by Candidate A is 16, while the number of wrong answers by Candidate B is 18. In order to determine the merit, Candidate A will be given higher preference in the order of merit, as the number of wrong answers by Candidate A is less than Candidate B.

Tie Breaker 5: This policy comes into effect only if the tie still persists after applying all the above rules. In such cases, candidates older in age will be given higher preference in the merit list. Check the example below for a better understanding.

Example:

Let us assume that Candidate A and Candidate B scored 240 marks in JEE Main Paper-II. On the other hand, these candidates scored the same marks in Mathematics, Aptitude Test and Drawing Test. At the same time, the number of incorrect answers by these candidates is also the same. However, Candidate A is 17 years and 6 months old and Candidate B is 17 years and 8 months old. As per tie-breaker policy 5, Candidate B will be given higher preference in the merit list.

JEE Main Syllabus 2023

The National Testing Agency (NTA) will publish the JEE Main syllabus 2023, as well as the official booklet, on its website. Students should be familiar with the NTA JEE Main 2023 curriculum PDF and exam format. Knowledge about the JEE Main syllabus 2023 will help students design a solid study schedule and study the relevant topics for the entrance test. The syllabus for JEE Mains 2023 is based on the 11th and 12th grade topics of Physics, Math, and Chemistry. As a result, students should begin their test preparation using the NTA JEE syllabus. Students are encouraged to take as many JEE Main 2023 mock tests as possible in order to have a better understanding of the exam's difficulty level and JEE 2023 syllabus.

How to Prepare for JEE Main 2023?

JEE Main is one of those exams that needs diligence, dedication, and a determination to achieve anything. Every year, over 10 lakh students take the exam, and everyone aspires to pass with flying colors. JEE Main 2023 students should review preparation strategy of JEE Main 2023 before starting their preparations.  A JEE Main preparation 2023 strategy along with the right approach will help the candidate in acing the JEE Main 2023.

Regardless of how difficult JEE Main looks to be, candidates can pass it in a single try if they are well-versed in some key themes of the entrance exam. Begin taking the All India Test Series (AITS) for JEE Main to ensure that you pass the test with flying colors.

Quick Links:

JEE Main College Predictor 2023
JEE Main Result 2023
JEE Main Rank Predictor 2023

FAQs about JEE Main Exam Pattern

How to Use JEE Main College Predictor Tool?

It is simple to use JEE Main college predictor tool. All that you need to do is to enter your JEE Main rank and select the category. Based on the previous years' data, the list of colleges, which are applicable for your rank will be displayed. 

Is there any negative marking for JEE Main Paper 2 Exam?

There is negative marking of -1 for MCQ based questions in JEE Main Paper 2 exam. Each wrong attempt by candidate will have a negative mark of -1

What is the total number of marks in JEE Main Paper 2 Exam?

JEE Main Paper 2 exam is conducted for 400 marks.

What is the total number of question for JEE Main Paper 2 Exam?

The total number of questions in JEE Main Paper 2 exam are 82 viz., 20+10 questions from Mathematics, 50 from Aptitude and 2 from Drawing Test.

What is the exam pattern for JEE Main Paper 2 Exam?

JEE Main Paper consists of three subjects, i.e., Mathematics, Aptitude Test and Drawing Test. The exam is conducted for 400 marks.

What is the mode of JEE Main Paper 2 Exam?

The mode of JEE Main Paper 2 exam is online (computer-based test).

What is the frequency of JEE Main Paper 2 Exam?

JEE Main Paper 2 exam is conducted four times a year., i.e., February, March, April and May.

What is JEE Main Paper 2 Exam?

JEE Main Paper 2 Exam is conducted for admission in B.Arch course.

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